答案：D

解析：

The function with equation y = ((-x)^2) + 1 and the function with equation y = |((x^2) + 1)| each have a minimum value of 1 when x = 0, but the function graphed does not have a minimum value of 1, so these options cannot be correct. The graph of the function with equation y = -(x^2) + 1 contains the point (2 , -3), but the function graphed does not contain any points with -y-coordinates, so this option cannot be correct. The graph of the function with equation y = |(x minus 1)^2| is not symmetric with respect to the y-axis, so it cannot be the equation of the function graphed. Therefore, the only equation that could correspond to the function graphed is y = |((x^2) minus 1)|. Its graph is the |of a parabola opening upward with vertex at (0 , -1).